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6u^2+5u-15=0
a = 6; b = 5; c = -15;
Δ = b2-4ac
Δ = 52-4·6·(-15)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{385}}{2*6}=\frac{-5-\sqrt{385}}{12} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{385}}{2*6}=\frac{-5+\sqrt{385}}{12} $
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